![]() ![]() ![]()
| |||
|
CHEMISTRY By Kingsley Idiagbor, B.Sc(Hons), PGDCs, NCE, MNSM
Chlorine is a member of Group VII in the periodic table of elements with the electronic configuration of 1s2 2s2 2p6 3s2 3p5. It is therefore one of the halogens ("salt formers") and was first isolated by Carl Scheele in the 18th century. The name, however. was given to it by Humphrey Davy who was the first to recognize it as an element and not a compound.
Occurrence: Chlorine does not occur in nature, but its
compounds are common minerals like Rock Salt. It is the 20th most abundant
element in the Earth's crust. Chlorine melts at -101° C (-149.8° F), boils
at -34.05° C (-29.29° F) at one atmosphere pressure, and has a relative
density of 1.41 at -35° C (-31° F); the relative atomic mass of the
element is 35.45.
Laboratory Preparation Chlorine is prepared in the laboratory by the action of hydrochloric acid (HCl) on strong oxidizing agent like manganese (IV) oxide (MnO2) and potassium tetraoxomanganate (VII) (KMnO4) crystals. The gas produced is led through a series of three Erlenmeyer flasks. The first flask is empty so as to prevent suck back phenomenon; the second contains ordinary water and this absorbs phosphine and other impurities from the gas while the last of the three flasks is filled with tetaoxosulphate (VI) acid (H2SO4) to dry the gas. The dried gas is collected in a gas jar by downward delivery. Equation for the reaction:
test for gas (i) Colour: Chlorine has a characteristic greenish-yellow
colour; PROPERTIES Cl2(g) + H2O (l) -----------> HCl(aq) + HOCl (aq) (ii) Bleaching Powder Chlorine is absorbed by calcium hydroxide to form bleaching powder: Cl2(g) +
Ca(OH)2(aq)-------->CaOCl2,H2O(s) Bleaching powder combines with trioxocarbonate(IV) acid present in the atmosphere to release chlorine gas. This explains why bleaching powder is considered a convenient medium of transporting chlorine. CaOCl2(s)+ H2CO3-------->CaCO3+H2O + Cl2 (iii)Bleaching action: Chlorine owes its bleaching action to the oxochlorate (I) acid, HOCl, formed when it is dissolved in water. First, the HOCl is broken down in the presence of sunlight to form an oxidizing agent, [O], and hydrochloric acid. Thereafter, the oxidizing agent, [O] binds to the dye in the material (such as litmus or fabric) to form a colourless complex, Dye-[O]. This is illustrated by the following set of equations: HOCl(aq) -------------> HCl(aq) +
[O] | |||
|